Multiple choice general knowledge math & puzzles

How many four digit numbers exist which can be formed by using the digits 2, 3, 5 and 7 once only such that they are divisible by 25?

  1. 4

  2. 5

  3. 6

  4. 7
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A Correct answer
Explanation

For a number to be divisible by 25, its last two digits must be either 25 or 75. Since we can only use each digit once (2, 3, 5, 7), the possible endings are: 25 or 75. For each ending, we have 2 digits remaining for the first two positions, which can be arranged in 2! = 2 ways. Total = 2 × 2 = 4 numbers.

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