To solve this question, the user needs to use basic arithmetic and algebraic concepts. The user must determine the number of friends in the group by setting up an equation based on the information given.
Let's assume that there were 'n' friends in the group, and each of them paid an equal amount of 'x' rupees for the dinner bill. Therefore, we can write the equation as:
nx = 2400
Since two friends forgot to bring their purses, the remaining (n-2) friends paid an extra Rs 100 each, so the new total amount becomes:
nx + 200 = 2400
Simplifying the above equation, we get:
nx = 2200
Dividing both sides of the equation by 'x', we get:
n = 2200/x
We know that 'n' is a positive integer. Therefore, to find the value of 'n', we need to find the factors of 2200 and check which factor yields a positive integer value of 'n'.
The factors of 2200 are: 1, 2, 4, 5, 10, 11, 20, 22, 25, 44, 50, 55, 100, 110, 220, 275, 550, 1100, and 2200.
Dividing 2200 by each of these factors, we get:
2200/1 = 2200
2200/2 = 1100
2200/4 = 550
2200/5 = 440
2200/10 = 220
2200/11 = 200 (positive integer)
2200/20 = 110
2200/22 = 100
2200/25 = 88
2200/44 = 50
2200/50 = 44
2200/55 = 40
2200/100 = 22
2200/110 = 20
2200/220 = 10
2200/275 = 8
2200/550 = 4
2200/1100 = 2
2200/2200 = 1
So the only factor that yields a positive integer value of 'n' is 11. Therefore, there were 11 friends in the group.
Option (C) 8 and option (D) 9 are not factors of 2200, so they are incorrect.
Option (A) 6 and option (B) 7 are factors of 2400, not 2200. Therefore, they are incorrect.
The Answer is: C