What is the remainder when 91 + 92 + 93 + .... + 98 is divided by 6 ?

91+92+93+94+95+96+97+98 = 703, and 703/6 = 117 remainder 1, so remainder is 1, not 0. Alternatively, note that consecutive integers have remainders cycling 1,2,3,4,5,0. Summing eight consecutive numbers gives remainders summing to 0 (if sum of 6 consecutive numbers). Checking: 91+98=189 (divisible by 3), 92+97=189, 93+96=189, 94+95=189. Total 756, which is divisible by 6, so remainder should be 0. But wait, 91+92+93+94+95+96+97+98 = 703? No, that's wrong. Let me recalculate: (91+98)+(92+97)+(93+96)+(94+95) = 189+189+189+189 = 756. 756/6 = 126 exactly. So remainder is 0. The claimed answer is correct.