To find out the number of gold coins the merchant has, we can solve the given problem using algebra.
Let's assume that the merchant has x gold coins. According to the problem, the merchant divides the coins into two unequal numbers.
Let's say the merchant divides the coins into two numbers, a and b, such that a > b.
According to the given information, we can form the following equation:
62(a - b) = a^2 - b^2
To solve this equation, let's simplify the equation using the difference of squares identity, (a^2 - b^2) = (a + b)(a - b):
62(a - b) = (a + b)(a - b)
Now, we can cancel out (a - b) from both sides:
62 = a + b
Since we know that a > b, we can deduce that a + b is the total number of gold coins the merchant has. Therefore, a + b = x.
Now, let's consider the answer options and substitute them into the equation a + b = x:
A) 82: 82 is not divisible by 62, so this option can be eliminated.
B) 62: If we substitute a = 62 and b = 0 into the equation, we get 62 + 0 = 62, which satisfies the condition. This option is a potential answer.
C) 42: 42 is not divisible by 62, so this option can be eliminated.
D) 22: 22 is not divisible by 62, so this option can be eliminated.
Thus, the correct answer is B) 62.