Multiple choice general knowledge science & technology

A car is moving in a straight line at speed of 90 km/hr. If break is applied such that car retards at rate of 4m/s-s. Find the distance covered by car in 8th second.

  1. 0 meters

  2. 0.25 meters

  3. 0.5 meters

  4. 1 meter
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

First convert speed: 90 km/hr = 25 m/s. Using v² = u² + 2as, the car stops when 0 = 625 - 8s, so total stopping distance = 78.125 m in 6.25 seconds. Time to stop: v = u + at gives 0 = 25 - 4t, so t = 6.25 s. Since the car stops before the 8th second begins, it covers zero distance during that second.

Keep practicing — related questions