Multiple choice general knowledge math & puzzles

a uniformally acclerating body is moving in a straight line. when it crosses point A its velocity is 2m/s and when it crosses point B its velocity is 14m/s. a point P is located such that AP:BP=1:5. find the velocity of the body at point P.

  1. 6m/s

  2. 4m/s

  3. 5m/s

  4. 8m/s
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A Correct answer
Explanation

For uniformly accelerated motion, velocity varies with the square root of distance traveled. Using v^2 = u^2 + 2as, if AP:PB = 1:5, then P is at 1/6 of the total distance from A. Solving gives v_P^2 = v_A^2 + (1/6)(v_B^2 - v_A^2), yielding v_P = 6 m/s. This is a standard kinematics relationship.

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