Multiple choice general knowledge math & puzzles

Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:

  1. 13

  2. 11

  3. 15

  4. 16
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C Correct answer
Explanation

Let the consecutive odd integers be n, n+2, n+4. Three times the first = 3n. Twice the third = 2(n+4). Equation: 3n = 2(n+4) + 3 = 2n + 8 + 3 = 2n + 11. Solving: 3n - 2n = 11, so n = 11. The integers are 11, 13, 15. The third integer is 15.

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