X is 25% more efficient than Y and his hourly wages are 25% more. If X is paid Rs.75, how much will Y receive for the same work?
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65
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90
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75
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110
Let Y's efficiency be 1 and wage be W. X's efficiency is 1.25 and wage is 1.25W. For the same work, X takes T/1.25 time. X's pay = (T/1.25) * 1.25W = TW = 75. Y's pay for the same work = T * W. Since TW = 75, Y also receives Rs.75.
To answer this question, let's calculate the hourly wages of Y and determine how much Y will receive for the same work.
Given that X is 25% more efficient than Y, we can say that if Y takes 100 units of time to complete a task, then X will take 75 units of time.
Now, let's consider the hourly wages. It is given that X's hourly wages are 25% more than Y's. So, if Y is paid Rs. 100 for 100 units of time, X will be paid Rs. 125 for 75 units of time.
To find out how much Y will receive for the same work, we need to calculate the amount paid per unit of time for Y.
Y's hourly wage = X's hourly wage * (100 units of time / 75 units of time)
Y's hourly wage = Rs. 125 * (100/75)
Y's hourly wage = Rs. 100
Therefore, Y will receive Rs. 100 for the same work.
The correct answer is C) 75.