how many 0's are ter in 100!
A
Correct answer
Explanation
The number of trailing zeros in n! equals the sum of floor(n/5) + floor(n/25) + floor(n/125) + ... For 100!, this is floor(100/5) + floor(100/25) + floor(100/125) + ... = 20 + 4 + 0 = 24 zeros. Each count adds the extra 5 factors from higher powers of 5.