Multiple choice general knowledge math & puzzles The smallest number which when diminished by 3 is divisible by 21,28,36 and 45 is... 869 859 1263 427 Reveal answer Fill a bubble to check yourself C Correct answer Explanation We need N-3 to be divisible by 21, 28, 36, and 45. Therefore N-3 must equal the LCM of these numbers. LCM(21,28,36,45) = LCM(3×7, 2²×7, 2²×3², 3²×5) = 2² × 3² × 5 × 7 = 4 × 9 × 5 × 7 = 1260. So N = 1260 + 3 = 1263.