Multiple choice general knowledge science & technology

If a gear transmits 2 KW at 1000 RPM what is the bending load on gear tooth if the PCD of the gear is 200 mm

  1. 60 x pi

  2. 600 x pi

  3. 600 / pi

  4. 60 / pi
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

To find the bending load on a gear tooth: Power = 2 KW, Speed = 1000 RPM, PCD = 200 mm. First, calculate torque: Torque = Power / Angular velocity. Angular velocity = (2π × RPM) / 60 = (2π × 1000) / 60 = 100π/3 rad/s. Torque = 2000 W / (100π/3) = 60/π Nm. Tangential force (bending load) = Torque / radius = (60/π) / 0.1 = 600/π N. The answer is 600/π, which matches option C.

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