Multiple choice general knowledge math & puzzles When x=1,then the value of (a-x)(b-x)....(z-x)? ((abc..z)-x)^2 abc...z 1 0 Reveal answer Fill a bubble to check yourself D Correct answer Explanation The expression (a-x)(b-x)...(z-x) contains the term (x-x) because the sequence includes every letter of the alphabet subtracted by x. Since (x-x) = 0, the entire product becomes 0 regardless of the value of other terms.