Multiple choice The sum of 1/ \frac{1}{x+y}x + y and \frac{1}{x-y} is <latex>\frac{2x}{x^2-y^2}</latex> <latex>\frac{2}{2x}</latex> <latex>\frac{2y}{x^2-y^2}</latex> <latex>\frac{-2x}{x^2-y^2}</latex> Reveal answer Fill a bubble to check yourself A Correct answer Explanation The sum is 1/(x + y) + 1/(x - y). Find a common denominator: (x - y)/((x + y)(x - y)) + (x + y)/((x + y)(x - y)) = (x - y + x + y) / (x^2 - y^2) = 2x / (x^2 - y^2).