Multiple choice

For the reaction, N2 + 3H2 → 2NH3, if d[NH3]/dt= 2 × 10–4 mol L–1 s–1,the value of d[H2]/dt would be

  1. 4 × 10–4 mol L–1 s–1

  2. 6 × 10–4 mol L–1 s–1

  3. 1 × 10–4 mol L–1 s–1

  4. 3 × 10–4 mol L–1 s–1
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D Correct answer
Explanation

From the stoichiometry, -d[N2]/dt = -(1/3)d[H2]/dt = (1/2)d[NH3]/dt. Given d[NH3]/dt = 2 * 10^-4, then -d[H2]/dt = (3/2) * d[NH3]/dt = 3 * 10^-4.

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