Multiple choice

$\sqrt 2$ and $\sqrt 8$ are irrational numbers. Their product will be _____.

  1. rational

  2. an integer

  3. irrational

  4. both (1) and (2)
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

$\sqrt 2 \times \sqrt 8 = \sqrt {16} = 4$is an integer and all the integers are rational numbers. So, $\sqrt 2 \times \sqrt 8$ is a rational number as well as an integer.

AI explanation

Multiplying the two irrational numbers gives sqrt(2) x sqrt(8) = sqrt(16) = 4. Even though each factor individually is irrational, their product simplifies to 4, which is both a rational number and an integer, so both descriptions apply at once.

Keep practicing — related questions