Multiple choice

Find the HCF of 410 and 96.

  1. 2

  2. 12

  3. 19680

  4. 39360
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A Correct answer
Explanation

The prime factorisation of 410 = 21 $\times$ 51 $\times$ 41 The prime factorisation of 96 = 25 $\times$ 3

2 410
5 205
41 41
  1
   

  ||| |---|---| | 2| 96| | 2| 48| | 2| 24| | 2| 12| | 2| 6| | 3| 3| | | 1|

HCF = Product of the smallest powers of each common prime factor in the numbers HCF (410, 96) = 21 = 2

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