Let the two consecutive odd positive integers be x and x + 2.
x(x + 2) = 483 $\Rightarrow$ x2 + 2x - 483 = 0
x2 + 23 x - 21 x - 483 = 0 $\Rightarrow$ x (x + 23) - 21 (x + 23) = 0
(x + 23) (x - 21) = 0
x = -23 , x - 21 => x = 21.
Since integers are positive, -23 can't be the answer.
So, the two integers are 21 and 23.
Two consecutive odd integers can be written as x and x+2. Setting x(x+2) = 483 gives x² + 2x – 483 = 0, which factors to (x–21)(x+23)=0, so x = 21. The two consecutive odd integers are therefore 21 and 23, and indeed 21×23 = 483.