Multiple choice

The reaction 2A $\to$ 2B + C obeys second order rate law. When the partial pressure of A is doubled, the rate would

  1. remain unchanged

  2. get doubled

  3. become four times the original

  4. reduce to half
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

When the partial pressure of A is doubled, its concentration gets doubled. Since rate = k (A)2, so the rate becomes four times the original.

AI explanation

For a second-order reaction, the rate law is rate = k[A]^2, meaning the rate depends on the square of the concentration (or partial pressure) of A. If the partial pressure of A is doubled, the rate becomes k(2P)^2 = 4kP^2, i.e., four times the original rate. This distinguishes second-order kinetics from first-order, where doubling a reactant's concentration only doubles the rate.

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