Multiple choice

The osmotic pressure of 5% sol of sucrose (M.M = 342) at 150 0 C, is

  1. 5.07 atm

  2. 5.007 atm

  3. 50.07 atm

  4. 500.07 atm
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A Correct answer
Explanation

The 5 % sol of sucrose means that 100 cm3 of sol contains 5 g of sucrose. Here, WB = 5 g, MB = 342 n mol-1, T = 150 + 273 = 423K, V = 0.100L, R = 0.082L atm mol-1K-1$\pi$  = nB/V RT = WBRT/MBRT =  5x0.082x423/342x0.100 = 5.07 atm

AI explanation

Osmotic pressure is calculated using π = CRT, where C is molar concentration. A 5% solution means 50 g of sucrose per litre; dividing by the molar mass 342 g/mol gives a concentration of about 0.146 mol/L. Multiplying by R (0.0821) and T (423 K, since 150°C = 423 K) gives π ≈ 5.07 atm.

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