Multiple choice Assuming i = $\sqrt{-1}$ and t is a real number, $\int\limits_0^\frac{x}{3}e^{it}dt$is $\frac{\sqrt{3}}{2}+i\frac{1}{2}$ $\frac{\sqrt{3}}{2}-i\frac{1}{2}$ $\frac{1}{2}+i\frac{\sqrt{3}}{2}$ $\frac{1}{2}+i\bigg(1-\frac{\sqrt{3}}{2}\bigg)$ Reveal answer Fill a bubble to check yourself A Correct answer Explanation