A simply supported beam of span length 6 m and 75 mm diameter carries a uniformly distributed load of 1.5 kN/m.
What is the maximum value of bending moment?
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$B.M.\frac{WL^2}{8}=\frac{1.5\times10^3\times(6)^2}{8}\\
B.M.=6750-m=6.75-m$Keep practicing — related questions
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