Multiple choice

If point A is in equilibrium under the action of the applied forces, the values of tensions and T AB, T AC are respectively.

  1. 520 N and 300 N

  2. 300 N and 520 N

  3. 450 N and 150 N

  4. 150 N and 450 N
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A Correct answer
Explanation

$T_{AB}=600\times\frac{\sqrt{3}}{2}=300\sqrt{3}\approx520N \\ T_{AC}=\frac{600}{2}=300N$

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