Given that the determinant of the matrix $\begin{bmatrix} \ 1 & 3 & 0 \ \ 2 & 6 & 4 \ \ -1 & 0 & 2 \ \end{bmatrix}$ is - 12, the determinant of the matrix $\begin{bmatrix} \ 2 & 6 & 0 \ \ 4 & 12 & 8 \ \ -2 & 0 & 4 \ \end{bmatrix}$ is
Reveal answer
Fill a bubble to check yourself
