Two steel truss members, AC and BC, each having cross sectional area of 100 mm2 are subjected to a horizontal force F as shown in figure, all the joints are hinged.
The maximum force F in kN that can be applied at C such that the axial stress in any of the truss members DOES NOT exceed 100 Mpa is
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$T_2 = 100 \times 100\\
0.8965F = 100 \times 100 \\
f = \frac{100 \times 100}{0.8965} = 11154.5N \\
F = 11.15kN$