Multiple choice

x + 2y + z = 4
2x + y + 2z = 5 x - y + z = 1

The system of algebraic equations given above has

  1. a unique solution of x = 1, y = 1 and z = 1

  2. only the two solutions of (x = 1, y = 1, z = 1) and (x = 2, y = 1, z = 0)

  3. infinite number of solutions

  4. no feasible solution
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

$\text{For given equation matrix form is as follow}\\ A = \begin{bmatrix} \ 1 & 2 & 1 \ \ 2 & 1 & 2 \ \ 1 & -1 & 1 \ \end{bmatrix}, B = \begin{bmatrix} \ 4 \ \ 5 \ \ 1 \ \end{bmatrix}$

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