Multiple choice

In the solution of the following set of linear equations by Gauss elimination using partial pivoting 5x + y + 2z = 34; 4y − 3z = 12 and 10x − 2y + z = −4 The pivots for elimination of x and y are

  1. 10 and 4

  2. 10 and 2

  3. 5 and 4

  4. 5 and – 4
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Explanation

Partial pivoting requires choosing the largest absolute value in the current column as the pivot. For the first column (x), the coefficients are 5, 0, 10; the largest is 10. After eliminating x, the remaining system is processed, and the largest available coefficient for y is chosen.

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