A frictionless fluid of density r flows through a bent pipe as shown below. If A is the cross sectional area and V is the velocity of flow, the forces exerted on segment 1-2 of the pipe in the x and y directions are, respectively
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$\rho AV^2; 0$
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$rAV^2; \sqrt{2} \rho AV^2$
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0; 0
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$0; \frac{1}{\sqrt{2}} \rho AV^2$
C
Correct answer
Explanation
Force = Change in momentum per second. but in the present case at section 1 and section 2 there is no change in either direction of velocity, magnitude of velocity and area of cross-section between section 1 and section 2. So $F_x = 0, F_y =0$