Multiple choice

For a pipe of radius r, flowing half full under the action of gravity, the hydraulic depth is

  1. r
  2. $\frac{\pi r}{4}$
  3. $\frac{r}{2}$

  4. 0379 r
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B Correct answer
Explanation

 $\text{Hydraulic depth} = \frac{\text{Area of the flow}}{\text{Total width at top of section}}\\ \hspace{1cm} = \frac{A}{T} = \frac{\pi /2 \times r^2}{2r} = \frac{\pi}{4}r$

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