A velocity vector is given as $\bar{V} = 5 xy \bar{i} + 2y^2 \bar{j} + 3yz^2 \bar{k}$ The divergence of this velocity vector at (1, 1, 1) is
Reveal answer
Fill a bubble to check yourself
Keep practicing — related questions
- Divergence of the vector field x2 zi + xyj – yz2 k at (1, - 1, 1) is
- The divergence of the vector field (x - y) $\hat{i}$ + (y - x) $\hat{j}$ + (x + y + z) $\hat{k}$ is
- The divergence of vector field 3xz$\hat{i}$ + 2xy$\hat{j}$-yz2$\hat{k}$at a point (1, 1, 1) is equal to
- A velocity field is given as $\bar{V} = 2 y \hat{i} + 3x \hat{j}$ where x and y are in metres. The accelera...
- What will be the output of the following code snippet? main() { int num=1; clrscr(); for(j=1;j<=6;j++) { fo...
- Consider the following statements: 1. The velocity of sound in shallow water is more than the velocity in d...
- Who among the following were the members of the Drafting Committee of the Constitution? (1) K. M. Munshi (2...
- Directions: Four parts of the sentence given below have been underlined. Identify the part having an error....