Multiple choice

Directions: Carry One Mark Each.

An air-standard diesel cycle consists of the following processes:

1–2: Air is compressed isentropically. 2–3: Heat is added at constant pressure. 3–4: Air expands isentropically to the original volume. 4–1: Heat is rejected at constant volume. If $\gamma$ and T respectively denote the specific heat ratio and temperature, then the efficiency of the cycle is

  1. $1-\frac{T_4-T_1}{T_3-T_2}$
  2. $1-\frac{T_4-T_1}{\gamma(T_3-T_2)}$
  3. $1-\frac{\gamma(T_4-T_1)}{T_3-T_2}$
  4. $1-\frac{T_4-T_1}{(\gamma-1)(T_3-T_2)}$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

For an air-standard diesel cycle,

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