A solid circular shaft of diameter d and length L is fixed at one end and free at the other end. A torque T is applied at the free end. The shear modulus of the material is G. The angle of twist at three free ends is
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$\frac{16TL}{\pi d^4 G}$
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$\frac{32TL}{\pi d^4 G}$
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$\frac{64TL}{\pi d^4 G}$
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$\frac{128TL}{\pi d^4 G}$
B
Correct answer
Explanation
The angle of twist for a circular shaft is given by the formula theta = TL / (GJ), where J is the polar moment of inertia. For a solid circular shaft, J = (pi * d^4) / 32. Substituting J gives theta = TL / (G * pi * d^4 / 32) = 32TL / (pi * d^4 * G).