Multiple choice

The order and degree of the differential equation $\frac{d^3y}{dx^3} + 4 \sqrt{(\frac{dy}{dx})^3 + y^3 = 0}$ are respectively

  1. 3 and 2

  2. 2 and 3

  3. 3 and 3

  4. 3 and 1
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The order of a differential equation is the highest derivative present, which is 3 here. To find the degree, we must make the equation polynomial in derivatives; squaring both sides of the radical term (d^3y/dx^3 + 4 * sqrt(...) = 0) leads to a term involving (d^3y/dx^3)^2, making the degree 2.

Keep practicing — related questions