Multiple choice

For flow through a pipe of radius R, the velocity and temperature distributions are as follow: u(r, x) = C1 and T(r, x) C2 $\bigg[1-(\frac{r}{R})^3\bigg]$, where C1 and C2 are constants. The bulk mean temperature is given by $T_m = \frac{2}{u_mR^2} \int\limits_0^R u(r, x)T (r, x) r dr$, with Um being the mean velocity of flow. The value of Tm is

  1. $\frac{0.5C_2}{U_m}$
  2. 0.5 C2

  3. 0.6C2

  4. $\frac{0.6C_2}{U_m}$
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C Correct answer
Explanation