Multiple choice

A rectangular open channel of width 5.0 m is carrying a discharge of 100/m3/s. The froude number of the flow is 0.8. The depth of flow (in m) in the channel is

  1. 4

  2. 5

  3. 16

  4. 20
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A Correct answer
Explanation

For a rectangular channel, the Froude number is Fr = v / sqrt(g * y). With Q = 100, B = 5, and v = Q / (B * y), we substitute into the Froude equation to solve for y. Solving 0.8 = (20/y) / sqrt(9.81 * y) yields y = 4 m.

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