Multiple choice

In a single throw of three dice, the probability of getting a total of 7 is

  1. 2/3

  2. 11/216

  3. 5/72

  4. 1/3

  5. 9/24
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Total number of exhaustive cases = 6 × 6 × 6 = 216. Cases favourable to get a total of 7 is = 12 that is, (1,1,5); (1,2,4); (1,3,3); (1,4,2); (1,5,1); (2,1,4); (2,2,3); (2,3,2); (2,4,1); (3,1,3); (3,2,2); (3,3,1); ( 4,1,2); (4,2,1); (5,1,1). Hence, the required probability is = 15 /216 = 5/72.

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