The ionic radii of N3-, O2-, F-, Na+ follows the order
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N3- > O2- > F- > Na+
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N3- > Na+ > O2- > F-
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Na+ > O2- > N3- > F-
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O2- > F- > Na+ > N3-
A
Correct answer
Explanation
Since all the species given in the option are isoelectronic and we know that for isoelectronic species, the ionic radii increases with decrease in nuclear charge and in the given question the order of decrease of nuclear charge is N3- > O2- > F- > Na+ which is the same as given in the option .