Multiple choice

The correct sequence for flow of electrons from excited P680* (in PS II) to P700 (reaction centre of PS I) is ________________.

  1. P680* → Pheophytin → Plastoquinone → Cytochrome b6-f complex → Plastocyanin → P 700

  2. P680* → Pheophytin → Cytochrome b6-f complex → Plastoquinone → Plastocyanin → P 700

  3. P680* → Plastocyanin → Plastoquinone → Cytochrome b6-f complex → Pheophytin → P 700

  4. P680* → Plastoquinone → Pheophytin → Plastocyanin → Cytochrome b6-f complex → P 700

  5. P680* → Plastoquinone → Pheophytin → Cytochrome b6-f complex → Plastocyanin → P 700
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A Correct answer
Explanation

The correct sequence for flow of electrons from excited P680* (in PS I) to P700 (reaction centre of PS II) is P680* → Pheophytin → Plastoquinone → Cytochrome b6-f complex → Plastocyanin → P 700. The excited form of P680, designated as P680*, is rapidly photo oxidized as it passes an electron to pheophytin, which is the primary electron acceptor of PS II. Reduced pheophytin, then hands on the electron to reduce plastoquinone. From reduced plastoquinone, electrons are accepted by cytochrom b6-f complex which gets reduced in this process. From reduced Cytochrome, b6-f complex electrons are taken up by plastocyanin, which is thus reduced. From reduced plastocyanin, electrons are accepted by P700, reaction centre of PS I, which is thus reduced.

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