Consider the declaration. int a = 5, b = &a; printf(“%d”, a*b); prints

Keep practicing — related questions

• Consider the following declaration. int a = 5, *b = &a; printf(“%d”, a*b);The above program prints
• what is the output? int a = 400; void main() { int b; b=(400 * 400)/ a ; printf("%d",b); }
• The statement printf (“%d”, sizeof(“”)); prints
• void main() { int a= 100; void *j= &a; int *k= j; printf("%u", *k); }
• What will be the output of the following: void main() { register int a; printf("%d",a); }
• Print the output of this program main() { int k = 5; if (++k < 5 && k++/5 || ++k <= 8); printf("%d\n", k); }
• main() { extern i; printf("%d",i); { int i=20; printf("%d",i); } }
• What is the output ? main() { int x=2000, *p, y = 200; p = &y; x = x/*p; printf("%d", x); }