Multiple choice Calculate the Tg of butadiene–styrene copolymer containing 20 vol% styrene. 44° C 44° C 80° C 80° C 100° C Reveal answer Fill a bubble to check yourself A Correct answer Explanation Butadiene and styrene form a completely compatible random copolymer. Therefore, the following relation is applicable: Tg = V1Tg1 + V2Tg2. Assume 1= polybutadiene 2 = polystyrene Tg1 = -80° C; Tg2 = 100° C Tg = 0.80 (-80) + 0.20 (100) = - 64 + 20 = - 44° C