The infinite product 3^(1/4) × 9^(1/8) × 27^(1/16) × ... = 3^(1/4 + 2/8 + 3/16 + ...). The exponent is sum of n/2^(n+1) for n=1 to infinity. Using the formula for sum of n/2^n = 2, we get exponent = 1/2 = 1. Therefore product = 3^1 = 3. This uses infinite series and geometric progression.