Multiple choice

Arrange the following in decreasing order of bond energy.

  1. F2 > Cl2 > Br2 > I2

  2. Cl2 > Br2 > F2 > I2

  3. F2 > Cl2 < Br2 > I2

  4. I2 > Br2 > Cl2 > F2

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B Correct answer
Explanation

pπ- pπ back bonding is there  in Cl due to which partial double bond character is there and hence, it is higher in order , but in case of bromine partial double bond, character is there but because of its large size double bond character is less than that in the case of Cl2 . This double bond character is not observe in case of iodine because of its large size . Florine has smaller in size than  iodine therefore it is above the iodine in order . Hence, the correct order  is Cl2 >  Br2 > F2 > I2 . 

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