Multiple choice

If the rate of electricity is rupee one per unit, then, a 20 h. p. electric motor, having approx. 100% efficiency will require how much cost (Rs.) on 100 hours running to irrigate the field?

  1. 500

  2. 1000

  3. 1500

  4. 2000

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

1 HP is approximately 0.746 kW. A 20 HP motor is 20 * 0.746 = 14.92 kW. For 100 hours, energy consumed is 1492 kWh. At 1 rupee per unit, the cost is 1492, which is closest to 1500.