Multiple choice

Three numbers are in the ratio 3 : 1 : 4 and the sum of these three numbers is 128. Then, the sum of the largest and the smallest number is

  1. 80

  2. 112

  3. 64

  4. 96

  5. None of these

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A Correct answer
Explanation

Let the numbers be 3x , x  and 4x, respectively. Then, 3x + x + 4x = 128  x = 16 Therefore, the three numbers are 48, 16, 64. Sum of the largest and the smallest number = 64 + 16 = 80.