Multiple choice

A radioactive element 82A214 undergoes two successive alpha emissions and one beta emission. What will be the atomic number and mass numbers of the product respectively?

  1. 85, 218

  2. 87, 223

  3. 79, 206

  4. 82, 215

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

82A214 undergoes alpha emission and becomes 80A210. Once again it undergoes alpha emission and becomes 78A206. Thereafter, it undergoes Beta emission and becomes 79A206.