Multiple choice

In a particular system, page size is 1KB. A process P wants to execute in that system, which requires 244658 bytes of memory for complete execution. Find out the number of frames (F) required for the execution of P and internal fragmentation (if any).

  1. 239 frames and there exists 70 bytes of internal fragmentation

  2. 239 frames required and no internal fragmentation

  3. 239 frames and paging doesn't suffer from external as well as internal fragmentation

  4. 238 frames and paging doesn't suffer from any type of fragmentation

  5. 239 frames and there exists 78 bytes of internal fragmentation
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

244658 / 1024 = 238.92 So, number of frames = 238 + 1 = 239 Internal fragmentation = (239 x 1024) - 244658 = 78 bytes Hence, this option is correct.

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