Multiple choice

The volume (in mL) of 0.2 M AgNO3 required for complete precipitation of chloride ions present in 50 mL of 0.02 M solution of [Cr(H2O)5Cl]Cl2, as silver chloride is __________.

  1. 1 mL

  2. 2 mL

  3. 5 mL

  4. 10 mL

  5. 20 mL
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

[Cr(H2O)5Cl]Cl2 + 2AgNO3 → 2AgCl + [Cr(H2O)5Cl](NO32 Number of ionisable chloride ions in complex [Cr(H2O)5Cl]Cl2 = 2. Millimoles = Molarity x Volume (mL) x 2= 0.02 x 50 x 2 = 2.0 Therefore, required Ag + ions = 2.0 millimoles Millimoles = Molarity x V (mL) 2.0 = 0.2 x V V = 10 mL

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