Multiple choice

What is the oxidation number of the platinum in [Pt (en) (H2O)2 (NO2) (Cl)]2+ ion?

    • 1

  2. � 2
    • 4

  4. � 1
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

In [Pt(en)(H2O)2(NO2)(Cl)]^2+: ethylenediamine (en) is neutral (0), each H2O is neutral (0), NO2^- is -1, Cl^- is -1, and the overall charge is +2. So: Pt + (0) + (0+0) + (-1) + (-1) = +2, therefore Pt = +4.

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