Multiple choice

During anaerobic respiration in yeast, how many glucose molecules are required for the production of 38 ATPs?

  1. 1

  2. 2

  3. 19

  4. 38

  5. 20
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C Correct answer
Explanation

During anaerobic respiration in yeast (fermentation), only 2 ATP molecules are produced per glucose molecule via glycolysis. To produce 38 ATPs, we need 38/2 = 19 glucose molecules. This calculation highlights the inefficiency of anaerobic respiration compared to aerobic respiration, where one glucose yields approximately 38 ATPs. The huge difference explains why organisms prefer aerobic respiration when oxygen is available.

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