An aircraft takes off at the speed of 100 km/hr at an angle of 30^o runaway. What is the velocity of the aircraft along the runway?

The velocity along the runway (horizontal component) = total velocity × cos(angle of takeoff). Given: v = 100 km/hr, angle = 30°. Horizontal component = 100 × cos(30°) = 100 × (√3/2) = 100 × 0.866 = 86.6 km/hr. This is the component parallel to the runway. The vertical component would be v × sin(30°) = 50 km/hr. Option B (76), C (70), and D (50 - which is the vertical component) are incorrect.