Multiple choice

15 men take 21 days of 8 hrs. each to do a piece of work. How many days of 6 hrs. each would it take for 21 women if 3 women do as much work as 2 men?

  1. 30

  2. 20

  3. 19

  4. 29

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Total work = 15 × 21 × 8 = 2520 man-hours. Since 3 women = 2 men, 21 women = 14 men. Let required days = d. Then 14 × d × 6 = 2520, giving 84d = 2520, so d = 30 days. Convert women's capacity to equivalent men using the given ratio.

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